Article: Q189917
Product(s): Microsoft FoxPro
Version(s): WINDOWS:5.0,5.0a,6.0
Operating System(s):
Keyword(s):
Last Modified: 11-DEC-1999
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The information in this article applies to:
- Microsoft Visual FoxPro for Windows, versions 5.0, 5.0a, 6.0
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SYMPTOMS
========
Releasing the variable assigned to a VisualFoxPro.Application COM object will
release the variable but will not terminate the application.
RESOLUTION
==========
In order to terminate the application, the QUIT method must be executed, as in
objMyVFPObject.Quit. Here's an example:
In the Command window, issue the following commands:
objMyVFPObject = CREATEOBJECT("visualfoxpro.application")
objMyVFPObject.visible = .t.
objMyVFPObject.QUIT
&&This releases the variable and terminates the application.
STATUS
======
This behavior is by design.
MORE INFORMATION
================
Releasing the assigned variable does not terminate the Visual FoxPro Application
object. The object's QUIT method must be used to terminate the Application
object.
Steps to Reproduce Behavior
---------------------------
1. In the Command window, issue the following commands:
objMyVFPObject = CREATEOBJECT("visualfoxpro.application")
objMyVFPObject.visible = .t.
RELEASE objMyVFPObject
&&This releases the variable but the application is still active.
Additional query words: kbVFp500a kbVFp600 kbXBase
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Keywords :
Technology : kbVFPsearch kbAudDeveloper kbVFP500 kbVFP600 kbVFP500a
Version : WINDOWS:5.0,5.0a,6.0
Issue type : kbprb
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